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0=2x^2+2x+1
We move all terms to the left:
0-(2x^2+2x+1)=0
We add all the numbers together, and all the variables
-(2x^2+2x+1)=0
We get rid of parentheses
-2x^2-2x-1=0
a = -2; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·(-2)·(-1)
Δ = -4
Delta is less than zero, so there is no solution for the equation
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